# Python program to find second largest
# number in a list
# list of numbers - length of
# list should be at least 2
list1 = [10, 20, 4, 45, 99]
mx = max(list1[0], list1[1])
secondmax = min(list1[0], list1[1])
n = len(list1)
for i in range(2,n):
if list1[i] > mx:
secondmax = mx
mx = list1[i]
elif list1[i] > secondmax and \
mx != list1[i]:
secondmax = list1[i]
elif mx == secondmax and \
secondmax != list1[i]:
secondmax = list1[i]
print("Second highest number is : ",\
str(secondmax))